\(\sqrt{3}\) के प्रमाण में अभाज्य (3) का सही तर्क कौन-सा है?

What is the correct argument using prime (3) in the proof of \(\sqrt{3}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. यदि \(3\mid u^2\) तो \(3\mid u\)If \(3\mid u^2\), then \(3\mid u\)

Step 1

Concept

A prime factor appears in a square only when it appears in the original number. This is the proof's key basis.

Step 2

Why this answer is correct

The correct answer is A. यदि \(3\mid u^2\) तो \(3\mid u\) / If \(3\mid u^2\), then \(3\mid u\). A prime factor appears in a square only when it appears in the original number. This is the proof's key basis.

Step 3

Exam Tip

अभाज्य गुणनखंड वर्ग में तभी आता है जब मूल संख्या में आता है। यही प्रमाण का मुख्य आधार है।

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Mathematics Answer, Explanation and Revision Hints

\(\sqrt{3}\) के प्रमाण में अभाज्य (3) का सही तर्क कौन-सा है? / What is the correct argument using prime (3) in the proof of \(\sqrt{3}\)?

Correct Answer: A. यदि \(3\mid u^2\) तो \(3\mid u\) / If \(3\mid u^2\), then \(3\mid u\). Explanation: अभाज्य गुणनखंड वर्ग में तभी आता है जब मूल संख्या में आता है। यही प्रमाण का मुख्य आधार है। / A prime factor appears in a square only when it appears in the original number. This is the proof's key basis.

Which concept should I revise for this Mathematics MCQ?

A prime factor appears in a square only when it appears in the original number. This is the proof's key basis.

What exam hint can help solve this Mathematics question?

अभाज्य गुणनखंड वर्ग में तभी आता है जब मूल संख्या में आता है। यही प्रमाण का मुख्य आधार है।