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In the contradiction proof for the irrationality of \(\sqrt{3}\), assume that \(\sqrt{3}=\frac{p}{q}\), where \(p\) and \(q\) are coprime. Why is the condition that \(p\) and \(q\) are coprime necessary?

Answer and explanation

Correct answer: Because the eventual result that both \(p\) and \(q\) are divisible by 3 contradicts this condition

From \(3q^2=p^2\), \(p\) must be divisible by 3. Putting \(p=3k\) then shows that \(q\) is also divisible by 3, contradicting coprimality. Exam tip: always assume the fraction is in lowest terms.

Related tags

Number SystemsIrrational NumbersSquare Root 3Proof By ContradictionCoprime NumbersProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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