वर्गमूल सर्पिल में \(\sqrt{2}\) बनाने के लिए किस प्रमेय से \(\sqrt{1^2+1^2}\) लिखा जाता है?
In a square root spiral, which theorem allows writing \(\sqrt{1^2+1^2}\) to make \(\sqrt{2}\)?
Explanation opens after your attempt
Correct Answer
A. पाइथागोरस प्रमेयPythagoras theorem
Concept
Pythagoras theorem is used for the hypotenuse in a right triangle. Thus \(\sqrt{1^2+1^2}=\sqrt{2}\).
Why this answer is correct
The correct answer is A. पाइथागोरस प्रमेय / Pythagoras theorem. Pythagoras theorem is used for the hypotenuse in a right triangle. Thus \(\sqrt{1^2+1^2}=\sqrt{2}\).
Exam Tip
समकोण त्रिभुज में कर्ण के लिए पाइथागोरस प्रमेय लगता है। इसलिए \(\sqrt{1^2+1^2}=\sqrt{2}\) मिलता है।
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