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In a square root spiral, in which situation will the hypotenuse not be a whole number?

Answer and explanation

Correct answer: When the hypotenuse is \(\sqrt{38}\)

\(16=4^2\), \(25=5^2\), and \(36=6^2\) are perfect squares, so their square roots are whole numbers. However, \(38\) is not a perfect square; it lies between \(36\) and \(49\). Therefore, \(\sqrt{38}\) is not a whole number. Exam tip: A square root is a whole number only when the number is a perfect square.

Related tags

Square Root SpiralPerfect SquaresIrrational NumbersNumber SystemsWhole NumbersMathematicsClass 9 Mcq

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