वर्गमूल सर्पिल में यदि \(\sqrt{n+1}\) अपरिमेय है, तो (n+1) के बारे में कौन-सा निष्कर्ष सही है?
In a square root spiral, if \(\sqrt{n+1}\) is irrational, what conclusion about (n+1) is correct?
Explanation opens after your attempt
Correct Answer
A. (n+1) पूर्ण वर्ग नहीं है(n+1) is not a perfect square
Concept
The square root of an integer is a whole number only when it is a perfect square. If it is not a perfect square, the square root can be irrational.
Why this answer is correct
The correct answer is A. (n+1) पूर्ण वर्ग नहीं है / (n+1) is not a perfect square. The square root of an integer is a whole number only when it is a perfect square. If it is not a perfect square, the square root can be irrational.
Exam Tip
पूर्णांक का वर्गमूल पूर्ण संख्या तभी होता है जब वह पूर्ण वर्ग हो। पूर्ण वर्ग न हो तो वर्गमूल अपरिमेय हो सकता है।
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