वर्गमूल सर्पिल में \(\sqrt{15}\) कर्ण पर (1) इकाई लंब बनाने से नया कर्ण बनने पर कौन-सा निष्कर्ष सही है?

In a square root spiral, after drawing a (1) unit perpendicular on hypotenuse \(\sqrt{15}\), which conclusion about the new hypotenuse is correct?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. नया कर्ण \(\sqrt{16}\) है और (4) के बराबर हैThe new hypotenuse is \(\sqrt{16}\) and equals (4)

Step 1

Concept

The new hypotenuse is \(\sqrt{15+1}=\sqrt{16}\). Since \(\sqrt{16}=4\), it is a whole number.

Step 2

Why this answer is correct

The correct answer is C. नया कर्ण \(\sqrt{16}\) है और (4) के बराबर है / The new hypotenuse is \(\sqrt{16}\) and equals (4). The new hypotenuse is \(\sqrt{15+1}=\sqrt{16}\). Since \(\sqrt{16}=4\), it is a whole number.

Step 3

Exam Tip

नया कर्ण \(\sqrt{15+1}=\sqrt{16}\) होगा। \(\sqrt{16}=4\), इसलिए यह पूर्ण संख्या है।

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वर्गमूल सर्पिल में \(\sqrt{15}\) कर्ण पर (1) इकाई लंब बनाने से नया कर्ण बनने पर कौन-सा निष्कर्ष सही है? / In a square root spiral, after drawing a (1) unit perpendicular on hypotenuse \(\sqrt{15}\), which conclusion about the new hypotenuse is correct?

Correct Answer: C. नया कर्ण \(\sqrt{16}\) है और (4) के बराबर है / The new hypotenuse is \(\sqrt{16}\) and equals (4). Explanation: नया कर्ण \(\sqrt{15+1}=\sqrt{16}\) होगा। \(\sqrt{16}=4\), इसलिए यह पूर्ण संख्या है। / The new hypotenuse is \(\sqrt{15+1}=\sqrt{16}\). Since \(\sqrt{16}=4\), it is a whole number.

Which concept should I revise for this Mathematics MCQ?

The new hypotenuse is \(\sqrt{15+1}=\sqrt{16}\). Since \(\sqrt{16}=4\), it is a whole number.

What exam hint can help solve this Mathematics question?

नया कर्ण \(\sqrt{15+1}=\sqrt{16}\) होगा। \(\sqrt{16}=4\), इसलिए यह पूर्ण संख्या है।