वर्गमूल सर्पिल में \(\sqrt{15}\) कर्ण पर (1) इकाई लंब बनाने से नया कर्ण बनने पर कौन-सा निष्कर्ष सही है?
In a square root spiral, after drawing a (1) unit perpendicular on hypotenuse \(\sqrt{15}\), which conclusion about the new hypotenuse is correct?
Explanation opens after your attempt
C. नया कर्ण \(\sqrt{16}\) है और (4) के बराबर हैThe new hypotenuse is \(\sqrt{16}\) and equals (4)
Concept
The new hypotenuse is \(\sqrt{15+1}=\sqrt{16}\). Since \(\sqrt{16}=4\), it is a whole number.
Why this answer is correct
The correct answer is C. नया कर्ण \(\sqrt{16}\) है और (4) के बराबर है / The new hypotenuse is \(\sqrt{16}\) and equals (4). The new hypotenuse is \(\sqrt{15+1}=\sqrt{16}\). Since \(\sqrt{16}=4\), it is a whole number.
Exam Tip
नया कर्ण \(\sqrt{15+1}=\sqrt{16}\) होगा। \(\sqrt{16}=4\), इसलिए यह पूर्ण संख्या है।
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