यदि \(y=\sqrt{8}+\sqrt{18}\) है तो \(\frac{y}{\sqrt{2}}\) का मान क्या है?
If \(y=\sqrt{8}+\sqrt{18}\), what is the value of \(\frac{y}{\sqrt{2}}\)?
Explanation opens after your attempt
Correct Answer
C. (5)
Concept
\(\sqrt{8}=2\sqrt{2}\) and \(\sqrt{18}=3\sqrt{2}\), so \(y=5\sqrt{2}\). Dividing gives (5).
Why this answer is correct
The correct answer is C. (5). \(\sqrt{8}=2\sqrt{2}\) and \(\sqrt{18}=3\sqrt{2}\), so \(y=5\sqrt{2}\). Dividing gives (5).
Exam Tip
\(\sqrt{8}=2\sqrt{2}\) और \(\sqrt{18}=3\sqrt{2}\), इसलिए \(y=5\sqrt{2}\) है। भाग देने पर (5) मिलता है।
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