यदि \(x=\sqrt{5}+\sqrt{2}\) और \(y=\sqrt{5}-\sqrt{2}\) हैं, तो \(\frac{x}{y}\) का मान क्या है?

If \(x=\sqrt{5}+\sqrt{2}\) and \(y=\sqrt{5}-\sqrt{2}\), what is the value of \(\frac{x}{y}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\frac{7+2\sqrt{10}}{3}\)

Step 1

Concept

Multiply by the conjugate \(\sqrt{5}+\sqrt{2}\). The denominator is (5-2=3) and the numerator is \(7+2\sqrt{10}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{7+2\sqrt{10}}{3}\). Multiply by the conjugate \(\sqrt{5}+\sqrt{2}\). The denominator is (5-2=3) and the numerator is \(7+2\sqrt{10}\).

Step 3

Exam Tip

हर के संयुग्मी \(\sqrt{5}+\sqrt{2}\) से गुणा करें। हर (5-2=3) और अंश \(7+2\sqrt{10}\) होगा।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(x=\sqrt{5}+\sqrt{2}\) और \(y=\sqrt{5}-\sqrt{2}\) हैं, तो \(\frac{x}{y}\) का मान क्या है? / If \(x=\sqrt{5}+\sqrt{2}\) and \(y=\sqrt{5}-\sqrt{2}\), what is the value of \(\frac{x}{y}\)?

Correct Answer: A. \(\frac{7+2\sqrt{10}}{3}\). Explanation: हर के संयुग्मी \(\sqrt{5}+\sqrt{2}\) से गुणा करें। हर (5-2=3) और अंश \(7+2\sqrt{10}\) होगा। / Multiply by the conjugate \(\sqrt{5}+\sqrt{2}\). The denominator is (5-2=3) and the numerator is \(7+2\sqrt{10}\).

Which concept should I revise for this Mathematics MCQ?

Multiply by the conjugate \(\sqrt{5}+\sqrt{2}\). The denominator is (5-2=3) and the numerator is \(7+2\sqrt{10}\).

What exam hint can help solve this Mathematics question?

हर के संयुग्मी \(\sqrt{5}+\sqrt{2}\) से गुणा करें। हर (5-2=3) और अंश \(7+2\sqrt{10}\) होगा।