यदि (x=1) और (y=-3), तो \(2x^2-xy+y^2\) का मान क्या होगा?

If (x=1) and (y=-3), what is the value of \(2x^2-xy+y^2\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. (14)

Step 1

Concept

(2(1)2-(1)(-3)+(-3)2=2+3+9=14). Watch negative multiplication and squares carefully.

Step 2

Why this answer is correct

The correct answer is C. (14). (2(1)2-(1)(-3)+(-3)2=2+3+9=14). Watch negative multiplication and squares carefully.

Step 3

Exam Tip

(2(1)2-(1)(-3)+(-3)2=2+3+9=14)। ऋणात्मक गुणन और वर्ग पर ध्यान दें।

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Mathematics Answer, Explanation and Revision Hints

यदि (x=1) और (y=-3), तो \(2x^2-xy+y^2\) का मान क्या होगा? / If (x=1) and (y=-3), what is the value of \(2x^2-xy+y^2\)?

Correct Answer: C. (14). Explanation: (2(1)2-(1)(-3)+(-3)2=2+3+9=14)। ऋणात्मक गुणन और वर्ग पर ध्यान दें। / (2(1)2-(1)(-3)+(-3)2=2+3+9=14). Watch negative multiplication and squares carefully.

Which concept should I revise for this Mathematics MCQ?

(2(1)2-(1)(-3)+(-3)2=2+3+9=14). Watch negative multiplication and squares carefully.

What exam hint can help solve this Mathematics question?

(2(1)2-(1)(-3)+(-3)2=2+3+9=14)। ऋणात्मक गुणन और वर्ग पर ध्यान दें।