यदि (p(x)=(k+3)x-12) का शून्यक (4) है, तो (k) का मान क्या है?
If the zero of (p(x)=(k+3)x-12) is (4), what is the value of (k)?
Explanation opens after your attempt
A. (0)
Concept
From (4(k+3)-12=0), we get (k=0). Substitute the zero into the polynomial and set it to (0).
Why this answer is correct
The correct answer is A. (0). From (4(k+3)-12=0), we get (k=0). Substitute the zero into the polynomial and set it to (0).
Exam Tip
(4(k+3)-12=0) से (k=0) मिलता है। शून्यक को बहुपद में रखकर (0) करें।
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