यदि \(t=\sqrt{19}+3\) है, तो \(t+\frac{10}{t}\) का मान क्या है?
If \(t=\sqrt{19}+3\), what is the value of \(t+\frac{10}{t}\)?
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{19}\)
Concept
\(\frac{10}{\sqrt{19}+3}=\sqrt{19}-3\) because the denominator becomes (19-9=10). So the sum is \(2\sqrt{19}\).
Why this answer is correct
The correct answer is A. \(2\sqrt{19}\). \(\frac{10}{\sqrt{19}+3}=\sqrt{19}-3\) because the denominator becomes (19-9=10). So the sum is \(2\sqrt{19}\).
Exam Tip
\(\frac{10}{\sqrt{19}+3}=\sqrt{19}-3\) है क्योंकि हर (19-9=10) बनता है। इसलिए योग \(2\sqrt{19}\) है।
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