यदि \(s=\sqrt{98}+\sqrt{200}\) है, तो \(\frac{s}{\sqrt{2}}\) का मान क्या है?
If \(s=\sqrt{98}+\sqrt{200}\), what is the value of \(\frac{s}{\sqrt{2}}\)?
Explanation opens after your attempt
Correct Answer
C. (17)
Concept
\(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{200}=10\sqrt{2}\), so \(s=17\sqrt{2}\). Dividing by \(\sqrt{2}\) gives (17).
Why this answer is correct
The correct answer is C. (17). \(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{200}=10\sqrt{2}\), so \(s=17\sqrt{2}\). Dividing by \(\sqrt{2}\) gives (17).
Exam Tip
\(\sqrt{98}=7\sqrt{2}\) और \(\sqrt{200}=10\sqrt{2}\), इसलिए \(s=17\sqrt{2}\) है। \(\sqrt{2}\) से भाग देने पर (17) मिलता है।
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