यदि (R(x)=\(x^5+3x^2\)2-x^{10}-6x-7+4x-4), तो (R(x)) की डिग्री क्या है?
If (R(x)=\(x^5+3x^2\)2-x^{10}-6x-7+4x-4), what is the degree of (R(x))?
Explanation opens after your attempt
C. (4)
Concept
(\(x^5+3x^2\)2=x^{10}+6x-7+9x-4). After higher terms cancel, \(13x^4\) remains, whose degree is (4).
Why this answer is correct
The correct answer is C. (4). (\(x^5+3x^2\)2=x^{10}+6x-7+9x-4). After higher terms cancel, \(13x^4\) remains, whose degree is (4).
Exam Tip
(\(x^5+3x^2\)2=x^{10}+6x-7+9x-4) होता है। बड़े पद कटने के बाद \(13x^4\) बचता है जिसकी डिग्री (4) है।
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