यदि \(r=\frac{1}{\sqrt{11}+3}\) है, तो (r) का सरल रूप कौन-सा है?

If \(r=\frac{1}{\sqrt{11}+3}\), which is the simplified form of (r)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\frac{\sqrt{11}-3}{2}\)

Step 1

Concept

Multiplying by the conjugate makes the denominator (11-9=2). So the simplified form is \(\frac{\sqrt{11}-3}{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{\sqrt{11}-3}{2}\). Multiplying by the conjugate makes the denominator (11-9=2). So the simplified form is \(\frac{\sqrt{11}-3}{2}\).

Step 3

Exam Tip

संयुग्मी से गुणा करने पर हर (11-9=2) बनता है। इसलिए सरल रूप \(\frac{\sqrt{11}-3}{2}\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(r=\frac{1}{\sqrt{11}+3}\) है, तो (r) का सरल रूप कौन-सा है? / If \(r=\frac{1}{\sqrt{11}+3}\), which is the simplified form of (r)?

Correct Answer: A. \(\frac{\sqrt{11}-3}{2}\). Explanation: संयुग्मी से गुणा करने पर हर (11-9=2) बनता है। इसलिए सरल रूप \(\frac{\sqrt{11}-3}{2}\) है। / Multiplying by the conjugate makes the denominator (11-9=2). So the simplified form is \(\frac{\sqrt{11}-3}{2}\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate makes the denominator (11-9=2). So the simplified form is \(\frac{\sqrt{11}-3}{2}\).

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर हर (11-9=2) बनता है। इसलिए सरल रूप \(\frac{\sqrt{11}-3}{2}\) है।