यदि सर्पिल में बिंदु \(P_6\) ऐसा है कि \(OP_6=\sqrt{6}\), तो अगले बने समकोण त्रिभुज का क्षेत्रफल कितना होगा?
If point \(P_6\) in the spiral satisfies \(OP_6=\sqrt{6}\), what is the area of the next right triangle formed?
Explanation opens after your attempt
Correct Answer
C. \( \frac{\sqrt{6}}{2} \)
Concept
The next triangle has perpendicular sides \( \sqrt{6} \) and (1). Its area is \( \frac{1}{2}\times \sqrt{6}\times 1=\frac{\sqrt{6}}{2} \).
Why this answer is correct
The correct answer is C. \( \frac{\sqrt{6}}{2} \). The next triangle has perpendicular sides \( \sqrt{6} \) and (1). Its area is \( \frac{1}{2}\times \sqrt{6}\times 1=\frac{\sqrt{6}}{2} \).
Exam Tip
अगले त्रिभुज की लंबवत भुजाएँ \( \sqrt{6} \) और (1) हैं। क्षेत्रफल \( \frac{1}{2}\times \sqrt{6}\times 1=\frac{\sqrt{6}}{2} \) होगा।
Login to save your score, XP, coins and progress.