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If (p(x)=x^4(x^2-4)-x^6+4x^4+17), what is the degree of (p(x))?यदि (p(x)=x^4(x^2-4)-x^6+4x^4+17), तो (p(x)) की डिग्री क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 00
First simplify the expression: \(x^4(x^2-4)=x^6-4x^4\). Thus, \(p(x)=x^6-4x^4-x^6+4x^4+17=17\). This is a non-zero constant polynomial, so its degree is \(0\). Choosing \(6\) or \(4\) would ignore the cancellation of like terms. Exam tip: always simplify a polynomial completely before finding its degree.पहले व्यंजक को सरल करें: \(x^4(x^2-4)=x^6-4x^4\)। अतः \(p(x)=x^6-4x^4-x^6+4x^4+17=17\)। यह एक अशून्य अचर बहुपद है, इसलिए इसकी डिग्री \(0\) होती है। \(6\) या \(4\) लेने की गलती तब होती है जब समान घात वाले पदों के निरस्तीकरण को नहीं देखा जाता। परीक्षा टिप: डिग्री ज्ञात करने से पहले बहुपद को पूरी तरह सरल अवश्य करें।
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