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If (p(x)=x^3(x^3-2)-x^6+2x^3+11), what is the degree of (p(x))?यदि (p(x)=x^3(x^3-2)-x^6+2x^3+11), तो (p(x)) की डिग्री क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 00
First simplify the expression:
\(x^3(x^3-2)=x^6-2x^3\). Hence,
\(p(x)=x^6-2x^3-x^6+2x^3+11=11\). This is a non-zero constant polynomial, so its degree is \(0\). Option 6 may seem likely from the initial terms, but the terms with equal powers cancel out. Exam tip: always simplify a polynomial completely before finding its degree.पहले व्यंजक को सरल कीजिए:
\(x^3(x^3-2)=x^6-2x^3\)। अतः
\(p(x)=x^6-2x^3-x^6+2x^3+11=11\)। यह एक अशून्य अचर बहुपद है, इसलिए इसकी डिग्री \(0\) होती है। विकल्प 6 प्रारम्भिक पद देखकर लग सकता है, लेकिन समान घात वाले पद परस्पर कट जाते हैं। परीक्षा टिप: डिग्री ज्ञात करने से पहले बहुपद को हमेशा पूरी तरह सरल करें।
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