यदि (p(x)=x-2+ax+a-2), तो (x) में इसकी घात कब (2) होगी?

If (p(x)=x-2+ax+a-2), when will its degree in (x) be (2)?

Explanation opens after your attempt
Correct Answer

C. सभी वास्तविक (a) के लिएFor all real (a)

Step 1

Concept

The coefficient of \(x^2\) is (1), which is non-zero. Therefore, the degree is (2) for every (a).

Step 2

Why this answer is correct

The correct answer is C. सभी वास्तविक (a) के लिए / For all real (a). The coefficient of \(x^2\) is (1), which is non-zero. Therefore, the degree is (2) for every (a).

Step 3

Exam Tip

\(x^2\) का गुणांक (1) है, जो शून्य नहीं है। इसलिए घात हर (a) के लिए (2) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=x-2+ax+a-2), तो (x) में इसकी घात कब (2) होगी? / If (p(x)=x-2+ax+a-2), when will its degree in (x) be (2)?

Correct Answer: C. सभी वास्तविक (a) के लिए / For all real (a). Explanation: \(x^2\) का गुणांक (1) है, जो शून्य नहीं है। इसलिए घात हर (a) के लिए (2) है। / The coefficient of \(x^2\) is (1), which is non-zero. Therefore, the degree is (2) for every (a).

Which concept should I revise for this Mathematics MCQ?

The coefficient of \(x^2\) is (1), which is non-zero. Therefore, the degree is (2) for every (a).

What exam hint can help solve this Mathematics question?

\(x^2\) का गुणांक (1) है, जो शून्य नहीं है। इसलिए घात हर (a) के लिए (2) है।