यदि (p(x)=x-2+ax+a-2), तो (x) में इसकी घात कब (2) होगी?
If (p(x)=x-2+ax+a-2), when will its degree in (x) be (2)?
Explanation opens after your attempt
C. सभी वास्तविक (a) के लिएFor all real (a)
Concept
The coefficient of \(x^2\) is (1), which is non-zero. Therefore, the degree is (2) for every (a).
Why this answer is correct
The correct answer is C. सभी वास्तविक (a) के लिए / For all real (a). The coefficient of \(x^2\) is (1), which is non-zero. Therefore, the degree is (2) for every (a).
Exam Tip
\(x^2\) का गुणांक (1) है, जो शून्य नहीं है। इसलिए घात हर (a) के लिए (2) है।
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