यदि \(OP=\sqrt{73}\) और \(OQ=\sqrt{74}\) लगातार कर्ण हैं, तो \(PQ^2\) क्या होगा?

If \(OP=\sqrt{73}\) and \(OQ=\sqrt{74}\) are consecutive hypotenuses, what is \(PQ^2\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (1)

Step 1

Concept

\(PQ^2=OQ^2-OP^2=74-73=1\). Therefore, the new perpendicular segment is (1) unit long.

Step 2

Why this answer is correct

The correct answer is B. (1). \(PQ^2=OQ^2-OP^2=74-73=1\). Therefore, the new perpendicular segment is (1) unit long.

Step 3

Exam Tip

\(PQ^2=OQ^2-OP^2=74-73=1\)। इसलिए नया लंब खंड (1) इकाई का है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(OP=\sqrt{73}\) और \(OQ=\sqrt{74}\) लगातार कर्ण हैं, तो \(PQ^2\) क्या होगा? / If \(OP=\sqrt{73}\) and \(OQ=\sqrt{74}\) are consecutive hypotenuses, what is \(PQ^2\)?

Correct Answer: B. (1). Explanation: \(PQ^2=OQ^2-OP^2=74-73=1\)। इसलिए नया लंब खंड (1) इकाई का है। / \(PQ^2=OQ^2-OP^2=74-73=1\). Therefore, the new perpendicular segment is (1) unit long.

Which concept should I revise for this Mathematics MCQ?

\(PQ^2=OQ^2-OP^2=74-73=1\). Therefore, the new perpendicular segment is (1) unit long.

What exam hint can help solve this Mathematics question?

\(PQ^2=OQ^2-OP^2=74-73=1\)। इसलिए नया लंब खंड (1) इकाई का है।