यदि \(OP=\sqrt{18}\) और नया (PQ=1) लंब है, तो (OQ) का सरलतम रूप क्या होगा?

If \(OP=\sqrt{18}\) and the new (PQ=1) is perpendicular, what will be the simplest form of (OQ)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. \(\sqrt{19}\)

Step 1

Concept

The new hypotenuse is \(\sqrt{18+1}=\sqrt{19}\). Since (19) is not a perfect square, this is already the simplest form.

Step 2

Why this answer is correct

The correct answer is C. \(\sqrt{19}\). The new hypotenuse is \(\sqrt{18+1}=\sqrt{19}\). Since (19) is not a perfect square, this is already the simplest form.

Step 3

Exam Tip

नया कर्ण \(\sqrt{18+1}=\sqrt{19}\) होगा। (19) पूर्ण वर्ग नहीं है, इसलिए यही सरल रूप है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(OP=\sqrt{18}\) और नया (PQ=1) लंब है, तो (OQ) का सरलतम रूप क्या होगा? / If \(OP=\sqrt{18}\) and the new (PQ=1) is perpendicular, what will be the simplest form of (OQ)?

Correct Answer: C. \(\sqrt{19}\). Explanation: नया कर्ण \(\sqrt{18+1}=\sqrt{19}\) होगा। (19) पूर्ण वर्ग नहीं है, इसलिए यही सरल रूप है। / The new hypotenuse is \(\sqrt{18+1}=\sqrt{19}\). Since (19) is not a perfect square, this is already the simplest form.

Which concept should I revise for this Mathematics MCQ?

The new hypotenuse is \(\sqrt{18+1}=\sqrt{19}\). Since (19) is not a perfect square, this is already the simplest form.

What exam hint can help solve this Mathematics question?

नया कर्ण \(\sqrt{18+1}=\sqrt{19}\) होगा। (19) पूर्ण वर्ग नहीं है, इसलिए यही सरल रूप है।