यदि \(\sqrt{65}\) तक कर्ण बने हैं, तो अंतिम कर्ण से (3) चरण पहले कौन सा कर्ण था?

If hypotenuses are constructed up to \(\sqrt{65}\), which hypotenuse was (3) steps before the final one?

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Correct Answer

B. \(\sqrt{62}\)

Step 1

Concept

Going (3) steps back gives (65-3=62). Therefore, the hypotenuse was \(\sqrt{62}\).

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{62}\). Going (3) steps back gives (65-3=62). Therefore, the hypotenuse was \(\sqrt{62}\).

Step 3

Exam Tip

(3) चरण पहले जाने पर (65-3=62) मिलता है। इसलिए कर्ण \(\sqrt{62}\) था।

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Mathematics Answer, Explanation and Revision Hints

यदि \(\sqrt{65}\) तक कर्ण बने हैं, तो अंतिम कर्ण से (3) चरण पहले कौन सा कर्ण था? / If hypotenuses are constructed up to \(\sqrt{65}\), which hypotenuse was (3) steps before the final one?

Correct Answer: B. \(\sqrt{62}\). Explanation: (3) चरण पहले जाने पर (65-3=62) मिलता है। इसलिए कर्ण \(\sqrt{62}\) था। / Going (3) steps back gives (65-3=62). Therefore, the hypotenuse was \(\sqrt{62}\).

Which concept should I revise for this Mathematics MCQ?

Going (3) steps back gives (65-3=62). Therefore, the hypotenuse was \(\sqrt{62}\).

What exam hint can help solve this Mathematics question?

(3) चरण पहले जाने पर (65-3=62) मिलता है। इसलिए कर्ण \(\sqrt{62}\) था।