यदि कोई विद्यार्थी \(\sqrt{52}+1=\sqrt{53}\) लिखकर अगला कर्ण बताता है, तो सही सुधार कौन-सा है?

If a student writes \(\sqrt{52}+1=\sqrt{53}\) to find the next hypotenuse, what is the correct correction?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (\sqrt{\(\sqrt{52}\)2+12}=\sqrt{53})

Step 1

Concept

Lengths are not added directly in a square root spiral. The correct method is to add squares by Pythagoras theorem.

Step 2

Why this answer is correct

The correct answer is B. (\sqrt{\(\sqrt{52}\)2+12}=\sqrt{53}). Lengths are not added directly in a square root spiral. The correct method is to add squares by Pythagoras theorem.

Step 3

Exam Tip

वर्गमूल सर्पिल में सीधे लंबाइयाँ नहीं जोड़ी जातीं। सही तरीका पाइथागोरस प्रमेय से वर्गों का योग लेना है।

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यदि कोई विद्यार्थी \(\sqrt{52}+1=\sqrt{53}\) लिखकर अगला कर्ण बताता है, तो सही सुधार कौन-सा है? / If a student writes \(\sqrt{52}+1=\sqrt{53}\) to find the next hypotenuse, what is the correct correction?

Correct Answer: B. (\sqrt{\(\sqrt{52}\)2+12}=\sqrt{53}). Explanation: वर्गमूल सर्पिल में सीधे लंबाइयाँ नहीं जोड़ी जातीं। सही तरीका पाइथागोरस प्रमेय से वर्गों का योग लेना है। / Lengths are not added directly in a square root spiral. The correct method is to add squares by Pythagoras theorem.

Which concept should I revise for this Mathematics MCQ?

Lengths are not added directly in a square root spiral. The correct method is to add squares by Pythagoras theorem.

What exam hint can help solve this Mathematics question?

वर्गमूल सर्पिल में सीधे लंबाइयाँ नहीं जोड़ी जातीं। सही तरीका पाइथागोरस प्रमेय से वर्गों का योग लेना है।