यदि \(a=\sqrt{18}+\sqrt{8}\) और \(b=\sqrt{18}-\sqrt{8}\) हैं तो \(a^2-b^2\) का मान क्या है?
If \(a=\sqrt{18}+\sqrt{8}\) and \(b=\sqrt{18}-\sqrt{8}\), what is the value of \(a^2-b^2\)?
Explanation opens after your attempt
Correct Answer
D. (48)
Concept
(a-2-b-2=(a-b)(a+b)), where \(a-b=2\sqrt{8}\) and \(a+b=2\sqrt{18}\). So the value is \(4\sqrt{144}=48\).
Why this answer is correct
The correct answer is D. (48). (a-2-b-2=(a-b)(a+b)), where \(a-b=2\sqrt{8}\) and \(a+b=2\sqrt{18}\). So the value is \(4\sqrt{144}=48\).
Exam Tip
(a-2-b-2=(a-b)(a+b)) है जहाँ \(a-b=2\sqrt{8}\) और \(a+b=2\sqrt{18}\) है। इसलिए मान \(4\sqrt{144}=48\) है।
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