यदि (a=1), (b=-2), तो \(4a^2b-3ab^2+b^3\) का मान क्या होगा?
If (a=1), (b=-2), what is the value of \(4a^2b-3ab^2+b^3\)?
Explanation opens after your attempt
A. (-28)
Concept
(4(1)(-2)-3(1)(4)+(-8)=-8-12-8=-28). Handle powers and signs carefully.
Why this answer is correct
The correct answer is A. (-28). (4(1)(-2)-3(1)(4)+(-8)=-8-12-8=-28). Handle powers and signs carefully.
Exam Tip
(4(1)(-2)-3(1)(4)+(-8)=-8-12-8=-28)। घात और चिन्ह दोनों सावधानी से लें।
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