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If (a=1), (b=-2), what is the value of (4a^2b-3ab^2+b^3)?यदि (a=1), (b=-2), तो (4a^2b-3ab^2+b^3) का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: -28-28
Given \(a=1\) and \(b=-2\), we have \(a^2=1\), \(b^2=4\), and \(b^3=-8\). Thus, \(4a^2b-3ab^2+b^3=4(1)(-2)-3(1)(4)+(-8)=-8-12-8=-28\). Therefore, \(-28\) is correct. The option \(-12\) is only the value of the second term, not of the complete expression. Exam tip: an odd power of a negative number is negative, while an even power is positive.दिया है: \(a=1\) और \(b=-2\)। इसलिए \(a^2=1\), \(b^2=4\) तथा \(b^3=-8\)। अब, \(4a^2b-3ab^2+b^3=4(1)(-2)-3(1)(4)+(-8)=-8-12-8=-28\)। अतः सही उत्तर \(-28\) है। \(-12\) विकल्प केवल दूसरे पद का मान है, पूरा व्यंजक नहीं। परीक्षा टिप: ऋणात्मक संख्या की विषम घात ऋणात्मक और सम घात धनात्मक होती है।
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