यदि \(a_1=96\) और \(a_{n+1}=\frac{a_n}{2}+n^2+n\) है तो \(a_3\) क्या होगा?
If \(a_1=96\) and \(a_{n+1}=\frac{a_n}{2}+n^2+n\), what is \(a_3\)?
Explanation opens after your attempt
C. (34)
Concept
\(a_2=48+2=50\) and \(a_3=25+6=31\). Exam tip: halve first and then add \(n^2+n\).
Why this answer is correct
The correct answer is C. (34). \(a_2=48+2=50\) and \(a_3=25+6=31\). Exam tip: halve first and then add \(n^2+n\).
Exam Tip
\(a_2=48+2=50\) और \(a_3=25+6=31\) है। सही विकल्पों में (31) होना चाहिए।
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