यदि \(a_1=7\) और \(a_{n+1}=a_n+na_1\) है तो \(a_4\) क्या होगा?

If \(a_1=7\) and \(a_{n+1}=a_n+na_1\), what is \(a_4\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (49)

Step 1

Concept

The terms are (7,14,28,49), so \(a_4=49\). Exam tip: \(a_1\) is fixed while (n) changes.

Step 2

Why this answer is correct

The correct answer is C. (49). The terms are (7,14,28,49), so \(a_4=49\). Exam tip: \(a_1\) is fixed while (n) changes.

Step 3

Exam Tip

पद (7,14,28,49) हैं इसलिए \(a_4=49\) है। \(a_1\) स्थिर है और (n) बदलता है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=7\) और \(a_{n+1}=a_n+na_1\) है तो \(a_4\) क्या होगा? / If \(a_1=7\) and \(a_{n+1}=a_n+na_1\), what is \(a_4\)?

Correct Answer: C. (49). Explanation: पद (7,14,28,49) हैं इसलिए \(a_4=49\) है। \(a_1\) स्थिर है और (n) बदलता है। / The terms are (7,14,28,49), so \(a_4=49\). Exam tip: \(a_1\) is fixed while (n) changes.

Which concept should I revise for this Mathematics MCQ?

The terms are (7,14,28,49), so \(a_4=49\). Exam tip: \(a_1\) is fixed while (n) changes.

What exam hint can help solve this Mathematics question?

पद (7,14,28,49) हैं इसलिए \(a_4=49\) है। \(a_1\) स्थिर है और (n) बदलता है।