यदि \(a_1=128\) और \(a_{n+1}=\frac{a_n}{4}\) है तो \(a_3\) क्या होगा?
If \(a_1=128\) and \(a_{n+1}=\frac{a_n}{4}\), what is \(a_3\)?
Explanation opens after your attempt
C. (8)
Concept
The terms are (128,32,8), so \(a_3=8\). Exam tip: divide the previous term by (4) each time.
Why this answer is correct
The correct answer is C. (8). The terms are (128,32,8), so \(a_3=8\). Exam tip: divide the previous term by (4) each time.
Exam Tip
पद (128,32,8) हैं इसलिए \(a_3=8\) है। हर बार पिछले पद को (4) से भाग दें।
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