यदि \(a_1=128\) और \(a_{n+1}=\frac{a_n}{4}\) है तो \(a_3\) क्या होगा?

If \(a_1=128\) and \(a_{n+1}=\frac{a_n}{4}\), what is \(a_3\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (8)

Step 1

Concept

The terms are (128,32,8), so \(a_3=8\). Exam tip: divide the previous term by (4) each time.

Step 2

Why this answer is correct

The correct answer is C. (8). The terms are (128,32,8), so \(a_3=8\). Exam tip: divide the previous term by (4) each time.

Step 3

Exam Tip

पद (128,32,8) हैं इसलिए \(a_3=8\) है। हर बार पिछले पद को (4) से भाग दें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=128\) और \(a_{n+1}=\frac{a_n}{4}\) है तो \(a_3\) क्या होगा? / If \(a_1=128\) and \(a_{n+1}=\frac{a_n}{4}\), what is \(a_3\)?

Correct Answer: C. (8). Explanation: पद (128,32,8) हैं इसलिए \(a_3=8\) है। हर बार पिछले पद को (4) से भाग दें। / The terms are (128,32,8), so \(a_3=8\). Exam tip: divide the previous term by (4) each time.

Which concept should I revise for this Mathematics MCQ?

The terms are (128,32,8), so \(a_3=8\). Exam tip: divide the previous term by (4) each time.

What exam hint can help solve this Mathematics question?

पद (128,32,8) हैं इसलिए \(a_3=8\) है। हर बार पिछले पद को (4) से भाग दें।