वर्गमूल सर्पिल में \(\sqrt{55}\) बनाने के बाद अगला कर्ण कौन-सा होगा और वह किस अंतराल में होगा?

After constructing \(\sqrt{55}\) in a square root spiral, what will be the next hypotenuse and in which interval will it lie?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\sqrt{56}\), (7) और (8) के बीच\(\sqrt{56}\), between (7) and (8)

Step 1

Concept

The next hypotenuse is \(\sqrt{56}\). Since \(7^2<56<8^2\), it lies between (7) and (8).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{56}\), (7) और (8) के बीच / \(\sqrt{56}\), between (7) and (8). The next hypotenuse is \(\sqrt{56}\). Since \(7^2<56<8^2\), it lies between (7) and (8).

Step 3

Exam Tip

अगला कर्ण \(\sqrt{56}\) है। क्योंकि \(7^2<56<8^2\), यह (7) और (8) के बीच होगा।

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वर्गमूल सर्पिल में \(\sqrt{55}\) बनाने के बाद अगला कर्ण कौन-सा होगा और वह किस अंतराल में होगा? / After constructing \(\sqrt{55}\) in a square root spiral, what will be the next hypotenuse and in which interval will it lie?

Correct Answer: A. \(\sqrt{56}\), (7) और (8) के बीच / \(\sqrt{56}\), between (7) and (8). Explanation: अगला कर्ण \(\sqrt{56}\) है। क्योंकि \(7^2<56<8^2\), यह (7) और (8) के बीच होगा। / The next hypotenuse is \(\sqrt{56}\). Since \(7^2<56<8^2\), it lies between (7) and (8).

Which concept should I revise for this Mathematics MCQ?

The next hypotenuse is \(\sqrt{56}\). Since \(7^2<56<8^2\), it lies between (7) and (8).

What exam hint can help solve this Mathematics question?

अगला कर्ण \(\sqrt{56}\) है। क्योंकि \(7^2<56<8^2\), यह (7) और (8) के बीच होगा।