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A student claims that if the square of an integer is divisible by 3, then the integer itself is divisible by 3. What is the correct evaluation of this claim?

Answer and explanation

Correct answer: दावा सत्य है, क्योंकि 3 से विभाज्य न होने वाले पूर्णांक का वर्ग 3 से विभाज्य नहीं हो सकता।

The claim is true. On division by 3, an integer leaves remainder 0, 1, or 2. Squaring remainders 1 and 2 gives remainders 1 and 4, i.e. 1 modulo 3, never 0. Hence a square divisible by 3 has a base divisible by 3. Exam tip: use remainders to test divisibility claims quickly.

Related tags

Number SystemsIrrationality ProofDivisibilityModular ArithmeticSquare Root 3Proof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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