असमानताओं \(x\geq 0\), \(y\geq 5\), \(x+y\leq 4\) का हल-क्षेत्र क्या है?
What is the solution region of \(x\geq 0\), \(y\geq 5\), and \(x+y\leq 4\)?
Explanation opens after your attempt
Correct Answer
D. खाली क्षेत्रEmpty region
Concept
If \(x\geq 0\) and \(y\geq 5\), then \(x+y\geq 5\). This contradicts \(x+y\leq 4\).
Why this answer is correct
The correct answer is D. खाली क्षेत्र / Empty region. If \(x\geq 0\) and \(y\geq 5\), then \(x+y\geq 5\). This contradicts \(x+y\leq 4\).
Exam Tip
यदि \(x\geq 0\) और \(y\geq 5\), तो \(x+y\geq 5\) होगा। यह \(x+y\leq 4\) से विरोध करता है।
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