Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 181-190 of 590 questions.
What is the value of \(\frac{7!}{5!}-\frac{6!}{4!}\)?
A. (12)
\(\frac{7!}{5!}=42\) और \(\frac{6!}{4!}=30\), इसलिए अंतर (12) है। छोटे अनुपात सीधे निकालें। / \(\frac{7!}{5!}=42\) and \(\frac{6!}{4!}=30\), so the difference is (12). Evaluate smaller ratios directly.
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What is the value of \(\frac{4!+5!}{3!}\)?
B. (24)
अंश (24+120=144) है और (3!=6)। इसलिए मान (24) है। / The numerator is (24+120=144) and (3!=6). Therefore, the value is (24).
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What is the value of \(\frac{12!}{10!,2!}-\frac{5!}{3!,2!}\)?
C. (56)
\(\frac{12!}{10!,2!}=66\) और \(\frac{5!}{3!,2!}=10\), इसलिए अंतर (56) है। बड़े और छोटे पद अलग रखें। / \(\frac{12!}{10!,2!}=66\) and \(\frac{5!}{3!,2!}=10\), so the difference is (56). Keep the larger and smaller terms separate.
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If (n(n-1)=72), what will be the value of (\frac{n!}{(n-2)!})?
B. (72)
(\frac{n!}{(n-2)!}=n(n-1))। दिए गए अनुसार इसका मान (72) है। / (\frac{n!}{(n-2)!}=n(n-1)). From the given condition, its value is (72).
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What is the value of \(\frac{6!}{5!}\times\frac{5!}{3!}\)?
C. (120)
पहला अनुपात (6) और दूसरा \(5\times4=20\) है। गुणनफल \(6\times20=120\) है। / The first ratio is (6) and the second is \(5\times4=20\). The product is \(6\times20=120\).
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What is the value of \(\frac{10!}{7!,3!}\)?
C. (120)
\(\frac{10!}{7!,3!}=\frac{10\times9\times8}{6}=120\)। (3!=6) रखना न भूलें। / \(\frac{10!}{7!,3!}=\frac{10\times9\times8}{6}=120\). Do not forget that (3!=6).
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What is the value of \(\frac{7!+5!}{6!}\)?
A. \(7+\frac{1}{6}\)
\(\frac{7!}{6!}=7\) और \(\frac{5!}{6!}=\frac{1}{6}\), इसलिए मान \(7+\frac{1}{6}\) है। पदों को हर से अलग-अलग भाग दें। / \(\frac{7!}{6!}=7\) and \(\frac{5!}{6!}=\frac{1}{6}\), so the value is \(7+\frac{1}{6}\). Divide each term by the denominator separately.
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If \(a=\frac{8!}{6!}\) and (b=3!), what is the value of (a-b)?
B. (50)
\(a=8\times7=56\) और (b=6), इसलिए (a-b=50)। पहले दोनों मान अलग निकालें। / \(a=8\times7=56\) and (b=6), so (a-b=50). Find both values separately first.
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What is the simplified form of (\frac{(n+2)!}{(n-1)!})?
A. ((n+2)(n+1)n)
((n+2)!=(n+2)(n+1)n(n-1)!)। इसलिए ((n-1)!) कटने पर तीन गुणक बचते हैं। / ((n+2)!=(n+2)(n+1)n(n-1)!). Hence after cancelling ((n-1)!), three factors remain.
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What is the value of \(\frac{9!}{8!}+\frac{8!}{7!}-\frac{7!}{6!}\)?
C. (10)
तीन अनुपात क्रमशः (9), (8) और (7) हैं। इसलिए (9+8-7=10) है। / The three ratios are (9), (8), and (7) respectively. Hence (9+8-7=10).
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