Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

Which situation is represented by (7x+y=10) and (14x+2y=25)?

Advertisement

Answer and explanation

Correct answer: Distinct parallel lines

For the two equations, \(\frac{a_1}{a_2}=\frac{7}{14}=\frac{1}{2}\) and \(\frac{b_1}{b_2}=\frac{1}{2}\), whereas \(\frac{c_1}{c_2}=\frac{10}{25}=\frac{2}{5}\). Thus, \(\frac{a_1}{a_2}=\frac{b_1}{b_2}\ne\frac{c_1}{c_2}\), which represents distinct parallel lines. Hence, the pair has no solution; option D states the algebraic consequence, but not the geometrical situation asked here. Exam tip: remember the condition \(\frac{a_1}{a_2}=\frac{b_1}{b_2}\ne\frac{c_1}{c_2}\) for distinct parallel lines.

Related tags

Linear EquationsParallel LinesConditions For SolvabilityNo SolutionCoordinate Geometry

Frequently asked questions

What is the correct answer to this question?

Distinct parallel lines

Why is this the correct answer?

For the two equations, \(\frac{a_1}{a_2}=\frac{7}{14}=\frac{1}{2}\) and \(\frac{b_1}{b_2}=\frac{1}{2}\), whereas \(\frac{c_1}{c_2}=\frac{10}{25}=\frac{2}{5}\). Thus, \(\frac{a_1}{a_2}=\frac{b_1}{b_2}\ne\frac{c_1}{c_2}\), which represents distinct parallel lines. Hence, the pair has no solution; option D states the algebraic consequence, but not the geometrical situation asked here. Exam tip: remember the condition \(\frac{a_1}{a_2}=\frac{b_1}{b_2}\ne\frac{c_1}{c_2}\) for distinct parallel lines.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Conditions for solvability.

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Advertisement