0 reads0 ratings0 helpful
Which of the following quadratic equations has non-real roots for every real value of \(m\)?
Advertisement
Answer and explanation
Correct answer: \(x^2+2mx+m^2+1=0\)
For option A, the discriminant is \(D=(2m)^2-4(m^2+1)=-4\), which is negative for every real \(m\). Hence its roots are non-real. In option B, \(D=4\). Exam tip: determine the sign of the discriminant first.
Frequently asked questions
What is the correct answer to this question?
\(x^2+2mx+m^2+1=0\)
Why is this the correct answer?
For option A, the discriminant is \(D=(2m)^2-4(m^2+1)=-4\), which is negative for every real \(m\). Hence its roots are non-real. In option B, \(D=4\). Exam tip: determine the sign of the discriminant first.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Nature of Roots.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement