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Which pair gives the roots of the equation \(x^2-(2m+1)x+m(m+1)=0\)?

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Answer and explanation

Correct answer: \(m\) and \(m+1\)

The polynomial factors as \(x^2-(2m+1)x+m(m+1)=(x-m)(x-(m+1))\). Hence, \(x=m\) or \(x=m+1\), so the roots are \(m\) and \(m+1\). As a quick check, the sum of the roots must be \(2m+1\) and their product must be \(m(m+1)\); option A satisfies both conditions. Exam tip: compare the sum and product of the proposed roots with the coefficients.

Related tags

Quadratic EquationsRoots Of Quadratic EquationsFactorisationVieta FormulasAlgebraic Identities

Frequently asked questions

What is the correct answer to this question?

\(m\) and \(m+1\)

Why is this the correct answer?

The polynomial factors as \(x^2-(2m+1)x+m(m+1)=(x-m)(x-(m+1))\). Hence, \(x=m\) or \(x=m+1\), so the roots are \(m\) and \(m+1\). As a quick check, the sum of the roots must be \(2m+1\) and their product must be \(m(m+1)\); option A satisfies both conditions. Exam tip: compare the sum and product of the proposed roots with the coefficients.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.

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