Which pair gives the roots of the equation \(x^2-(2m+1)x+m(m+1)=0\)?
Answer and explanation
Correct answer: \(m\) and \(m+1\)
The polynomial factors as \(x^2-(2m+1)x+m(m+1)=(x-m)(x-(m+1))\). Hence, \(x=m\) or \(x=m+1\), so the roots are \(m\) and \(m+1\). As a quick check, the sum of the roots must be \(2m+1\) and their product must be \(m(m+1)\); option A satisfies both conditions. Exam tip: compare the sum and product of the proposed roots with the coefficients.
Frequently asked questions
What is the correct answer to this question?
\(m\) and \(m+1\)
Why is this the correct answer?
The polynomial factors as \(x^2-(2m+1)x+m(m+1)=(x-m)(x-(m+1))\). Hence, \(x=m\) or \(x=m+1\), so the roots are \(m\) and \(m+1\). As a quick check, the sum of the roots must be \(2m+1\) and their product must be \(m(m+1)\); option A satisfies both conditions. Exam tip: compare the sum and product of the proposed roots with the coefficients.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.
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