Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

When will ((p+4)x-9y=2) and (5x-15y=6) have a unique solution?

Advertisement

Answer and explanation

Correct answer: \(p\neq -1\)

A pair of linear equations has a unique solution when the ratios of the coefficients of x and y are unequal. Here, the condition is \(\frac{p+4}{5}\neq\frac{-9}{-15}\). Since \(\frac{-9}{-15}=\frac{3}{5}\), we need \(\frac{p+4}{5}\neq\frac{3}{5}\), which gives \(p\neq -1\). At \(p=-1\), the x- and y-coefficient ratios become equal, so the solution cannot be unique. Exam tip: for a unique solution, first compare the ratios of the coefficients of x and y.

Related tags

Class 10 MathematicsPair Of Linear EquationsUnique SolutionSolvability ConditionsCoefficient Ratios

Frequently asked questions

What is the correct answer to this question?

\(p\neq -1\)

Why is this the correct answer?

A pair of linear equations has a unique solution when the ratios of the coefficients of x and y are unequal. Here, the condition is \(\frac{p+4}{5}\neq\frac{-9}{-15}\). Since \(\frac{-9}{-15}=\frac{3}{5}\), we need \(\frac{p+4}{5}\neq\frac{3}{5}\), which gives \(p\neq -1\). At \(p=-1\), the x- and y-coefficient ratios become equal, so the solution cannot be unique. Exam tip: for a unique solution, first compare the ratios of the coefficients of x and y.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Conditions for solvability.

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Advertisement