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What type of pair is formed by (4x+3y=10) and (8x+6y=21)?समीकरण (4x+3y=10) और (8x+6y=21) किस प्रकार का युग्म बनाते हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Inconsistentअसंगत
Here (4/8=3/6) but (10/21) is different so there is no solution. Equal first two ratios and a different third ratio mean parallel lines.यहां (4/8=3/6) लेकिन (10/21) अलग है इसलिए कोई हल नहीं। पहले दो अनुपात बराबर और तीसरा अलग हो तो रेखाएं समानांतर होती हैं।
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