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For the polynomial \(p(x)=x^4-5x^2+4\), what is the value of \(p(-2)\)?

Answer and explanation

Correct answer: 0

Substituting \(x=-2\), \(p(-2)=(-2)^4-5(-2)^2+4=16-5(4)+4=16-20+4=0\). Since the powers are even, \((-2)^4=16\) and \((-2)^2=4\). Option B results from an incomplete calculation, so it is incorrect. In exams, substitute the value first, evaluate powers, and then perform multiplication and subtraction.

Related tags

Polynomial EvaluationSubstitutionEven PowersPolynomials In One VariablePolynomialsMathematicsClass 10 Mcq

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