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What is the sum of squares of the roots of \(6x^2+7x+2=0\)?
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Answer and explanation
Correct answer: \( \frac{25}{36} \)
\(\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta\). Here \(\left(-\frac{7}{6}\right)^2-2\cdot\frac{1}{3}=\frac{25}{36}\).
Frequently asked questions
What is the correct answer to this question?
\( \frac{25}{36} \)
Why is this the correct answer?
\(\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta\). Here \(\left(-\frac{7}{6}\right)^2-2\cdot\frac{1}{3}=\frac{25}{36}\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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