What is the sum of reciprocals of the roots of (6x^2-19x+10=0)?
Answer and explanation
Correct answer: ( \frac{19}{10} )
The sum of reciprocals is (\frac{\alpha+\beta}{\alpha\beta}). Here it is (\frac{\frac{19}{6}}{\frac{10}{6}}=\frac{19}{10}).
Frequently asked questions
What is the correct answer to this question?
( \frac{19}{10} )
Why is this the correct answer?
The sum of reciprocals is (\frac{\alpha+\beta}{\alpha\beta}). Here it is (\frac{\frac{19}{6}}{\frac{10}{6}}=\frac{19}{10}).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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