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What is the sum of reciprocals of the roots of (4x^2-13x+9=0)?
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Answer and explanation
Correct answer: ( \frac{13}{9} )
The sum of reciprocals is (\frac{\alpha+\beta}{\alpha\beta}). Here it is (\frac{\frac{13}{4}}{\frac{9}{4}}=\frac{13}{9}).
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What is the correct answer to this question?
( \frac{13}{9} )
Why is this the correct answer?
The sum of reciprocals is (\frac{\alpha+\beta}{\alpha\beta}). Here it is (\frac{\frac{13}{4}}{\frac{9}{4}}=\frac{13}{9}).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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