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Subjects
Class 10MathematicsQuadratic EquationsIntroduction to Quadratic EquationsHardLevel 30
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What is the standard quadratic form of ((6x+1)(x-4)=5x)?

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Answer and explanation

Correct answer: (6x^2-28x-4=0)

Here ((6x+1)(x-4)=6x^2-23x-4), and subtracting (5x) gives (6x^2-28x-4=0). First expand and then bring all terms to one side.

Related tags

Quadratic-EquationsStandard-FormExpansionHard

Frequently asked questions

What is the correct answer to this question?

(6x^2-28x-4=0)

Why is this the correct answer?

Here ((6x+1)(x-4)=6x^2-23x-4), and subtracting (5x) gives (6x^2-28x-4=0). First expand and then bring all terms to one side.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.

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10 more MCQs
  1. 1Which of the following equations is a quadratic equation?
  2. 2What is the value of \(a\) in the equation \(5x^2-2x+9=0\)?
  3. 3What is the value of \(b\) in \(3x^2+7x-4=0\)?
  4. 4In the equation \(4x^2-8x+1=0\), what is the value of \(c\)?
  5. 5In the quadratic equation \(x^2-6x=0\), what is the value of the constant term (c)?
  6. 6What is the value of \(x\) in the equation \(9x^2 + 11 = 0\)?
  7. 7Under which condition is the equation \(ax^2+bx+c=0\) called a quadratic equation?
  8. 8What is the standard form of the equation \(2x^2+5x=3\)?
  9. 9What is the standard form of the equation \(x^2 = 4x + 12\)?
  10. 10Which of the following equations is written in the standard form \(ax^2+bx+c=0\)?
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