समीकरणों \(\frac{x}{2}+\frac{y}{3}=7\) और \(\frac{x}{3}-\frac{y}{2}=1\) का हल क्या है?

What is the solution of \(\frac{x}{2}+\frac{y}{3}=7\) and \(\frac{x}{3}-\frac{y}{2}=1\)?

Explanation opens after your attempt
Correct Answer

B. \(x=\frac{138}{13},\ y=\frac{66}{13}\)

Step 1

Concept

Clear the denominators using the LCM first. The solution is \(x=\frac{138}{13},\ y=\frac{66}{13}\).

Step 2

Why this answer is correct

The correct answer is B. \(x=\frac{138}{13},\ y=\frac{66}{13}\). Clear the denominators using the LCM first. The solution is \(x=\frac{138}{13},\ y=\frac{66}{13}\).

Step 3

Exam Tip

हरों का लघुत्तम समापवर्त्य लेकर समीकरणों को सरल करें। हल \(x=\frac{138}{13},\ y=\frac{66}{13}\) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

समीकरणों \(\frac{x}{2}+\frac{y}{3}=7\) और \(\frac{x}{3}-\frac{y}{2}=1\) का हल क्या है? / What is the solution of \(\frac{x}{2}+\frac{y}{3}=7\) and \(\frac{x}{3}-\frac{y}{2}=1\)?

Correct Answer: B. \(x=\frac{138}{13},\ y=\frac{66}{13}\). Explanation: हरों का लघुत्तम समापवर्त्य लेकर समीकरणों को सरल करें। हल \(x=\frac{138}{13},\ y=\frac{66}{13}\) मिलता है। / Clear the denominators using the LCM first. The solution is \(x=\frac{138}{13},\ y=\frac{66}{13}\).

Which concept should I revise for this Mathematics MCQ?

Clear the denominators using the LCM first. The solution is \(x=\frac{138}{13},\ y=\frac{66}{13}\).

What exam hint can help solve this Mathematics question?

हरों का लघुत्तम समापवर्त्य लेकर समीकरणों को सरल करें। हल \(x=\frac{138}{13},\ y=\frac{66}{13}\) मिलता है।