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Class 10MathematicsQuadratic EquationsRoots of a Quadratic EquationEasyLevel 33
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What is the repeated root of the equation \(x^2-12x+36=0\)?

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Answer and explanation

Correct answer: 6

The equation can be written as \(x^2-12x+36=(x-6)^2\). Thus, \((x-6)^2=0\), giving \(x=6\), which is the repeated root. Exam tip: In a perfect-square quadratic equation, set the expression inside the square equal to zero to find the repeated root.

Related tags

Quadratic EquationsRootsRepeated RootPerfect SquareDiscriminant

Frequently asked questions

What is the correct answer to this question?

6

Why is this the correct answer?

The equation can be written as \(x^2-12x+36=(x-6)^2\). Thus, \((x-6)^2=0\), giving \(x=6\), which is the repeated root. Exam tip: In a perfect-square quadratic equation, set the expression inside the square equal to zero to find the repeated root.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.

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