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What is the nature of the roots of the quadratic equation \(x^2-6x+9=0\)?
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Answer and explanation
Correct answer: दो वास्तविक और समान मूल
Here \(a=1, b=-6, c=9\). The discriminant is \(D=b^2-4ac=(-6)^2-4(1)(9)=0\), so the roots are real and equal. Distinct real roots occur only when \(D>0\). Exam tip: check the discriminant first to identify the nature of roots.
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What is the correct answer to this question?
दो वास्तविक और समान मूल
Why is this the correct answer?
Here \(a=1, b=-6, c=9\). The discriminant is \(D=b^2-4ac=(-6)^2-4(1)(9)=0\), so the roots are real and equal. Distinct real roots occur only when \(D>0\). Exam tip: check the discriminant first to identify the nature of roots.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.
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