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What is the nature of the roots of the quadratic equation \(16x^2-24kx+9k^2=0\)?

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Answer and explanation

Correct answer: Two equal real roots

The equation can be written as \((4x-3k)^2=0\). Hence \(4x-3k=0\), giving the repeated root \(x=\frac{3k}{4}\). Equivalently, the discriminant is \(D=b^2-4ac=0\), which confirms that the roots are equal and real. Exam tip: for a quadratic equation, \(D=0\) indicates two equal real roots.

Related tags

Quadratic-EquationsDiscriminantPerfect-SquareNature-Of-Roots

Frequently asked questions

What is the correct answer to this question?

Two equal real roots

Why is this the correct answer?

The equation can be written as \((4x-3k)^2=0\). Hence \(4x-3k=0\), giving the repeated root \(x=\frac{3k}{4}\). Equivalently, the discriminant is \(D=b^2-4ac=0\), which confirms that the roots are equal and real. Exam tip: for a quadratic equation, \(D=0\) indicates two equal real roots.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.

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