संख्या 529200 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 529200?

Explanation opens after your attempt
Correct Answer

A. \(2^4\times3^3\times5^2\times7^2\)

Step 1

Concept

Write \(529200=16\times33075\).

Step 2

Why this answer is correct

\(33075=3^3\times5^2\times7^2\), so \(529200=2^4\times3^3\times5^2\times7^2\).

Step 3

Exam Tip

Do not leave 33075 in the final form. चरण 1: \(529200=16\times33075\) लिखें। चरण 2: \(33075=3^3\times5^2\times7^2\), इसलिए \(529200=2^4\times3^3\times5^2\times7^2\)। चरण 3: 33075 को अंतिम रूप में न छोड़ें।

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संख्या 529200 का सही अभाज्य गुणनखंडन क्या है? / What is the correct prime factorisation of 529200?

Correct Answer: A. \(2^4\times3^3\times5^2\times7^2\). Explanation: चरण 1: \(529200=16\times33075\) लिखें। चरण 2: \(33075=3^3\times5^2\times7^2\), इसलिए \(529200=2^4\times3^3\times5^2\times7^2\)। चरण 3: 33075 को अंतिम रूप में न छोड़ें। / Step 1: Write \(529200=16\times33075\). Step 2: \(33075=3^3\times5^2\times7^2\), so \(529200=2^4\times3^3\times5^2\times7^2\). Step 3: Do not leave 33075 in the final form.

Which concept should I revise for this Mathematics MCQ?

Write \(529200=16\times33075\).

What exam hint can help solve this Mathematics question?

Do not leave 33075 in the final form. चरण 1: \(529200=16\times33075\) लिखें। चरण 2: \(33075=3^3\times5^2\times7^2\), इसलिए \(529200=2^4\times3^3\times5^2\times7^2\)। चरण 3: 33075 को अंतिम रूप में न छोड़ें।