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Class 10MathematicsPolynomialsPolynomials in one variableMedium
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If \(p(x)=x^2+6x+9\), what is the value of \(p(-3)\)?

Answer and explanation

Correct answer: 0

Substituting \(x=-3\), \(p(-3)=(-3)^2+6(-3)+9=9-18+9=0\). Therefore, 0 is the correct value, and \(-3\) is a zero of the polynomial. Choosing 9 usually results from omitting the term \(6(-3)\). In an exam, enclose a negative value in parentheses while substituting.

Related tags

PolynomialsPolynomial EvaluationZeros Of PolynomialsQuadratic PolynomialPolynomials In One VariableMathematicsClass 10 Mcq
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  1. 1If (p(x)=x²−8x+10), what are its zeroes?
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  5. 5If p(x) = x² − 2√2x + 2, which is the correct factorized form of p(x)?
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  8. 8Which expression is a polynomial in one variable (x)?
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  10. 10What is the constant term of the polynomial \(7x^2+5x-11\)?
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