The roots of (x^2+px+49=0) are equal and negative. What is the value of (p)?
Answer and explanation
Correct answer: (14)
For equal roots, (p^2-196=0) gives (p=\pm14). For equal negative roots, (-\frac{p}{2}<0), so (p=14).
Frequently asked questions
What is the correct answer to this question?
(14)
Why is this the correct answer?
For equal roots, (p^2-196=0) gives (p=\pm14). For equal negative roots, (-\frac{p}{2}<0), so (p=14).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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