समीकरण \(x^2-4x+1=0\) के मूल \(\alpha,\beta\) हैं। \(\alpha+\beta+\alpha\beta\) का मान क्या है?

The roots of \(x^2-4x+1=0\) are \(\alpha,\beta\). What is \(\alpha+\beta+\alpha\beta\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

The sum of roots is (4) and the product is (1). Therefore \(\alpha+\beta+\alpha\beta=5\).

Step 2

Why this answer is correct

The correct answer is A. (5). The sum of roots is (4) and the product is (1). Therefore \(\alpha+\beta+\alpha\beta=5\).

Step 3

Exam Tip

मूलों का योग (4) और गुणनफल (1) है। इसलिए \(\alpha+\beta+\alpha\beta=5\)।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(x^2-4x+1=0\) के मूल \(\alpha,\beta\) हैं। \(\alpha+\beta+\alpha\beta\) का मान क्या है? / The roots of \(x^2-4x+1=0\) are \(\alpha,\beta\). What is \(\alpha+\beta+\alpha\beta\)?

Correct Answer: A. (5). Explanation: मूलों का योग (4) और गुणनफल (1) है। इसलिए \(\alpha+\beta+\alpha\beta=5\)। / The sum of roots is (4) and the product is (1). Therefore \(\alpha+\beta+\alpha\beta=5\).

Which concept should I revise for this Mathematics MCQ?

The sum of roots is (4) and the product is (1). Therefore \(\alpha+\beta+\alpha\beta=5\).

What exam hint can help solve this Mathematics question?

मूलों का योग (4) और गुणनफल (1) है। इसलिए \(\alpha+\beta+\alpha\beta=5\)।