0 reads0 ratings0 helpful
The length of a rectangle is \(x+3\) cm and its breadth is \(x-2\) cm. If its area is \(40\) cm², which is the correct quadratic equation in \(x\)?
Advertisement
Answer and explanation
Correct answer: \(x^2+x-46=0\)
For area, write \((x+3)(x-2)=40\). Expanding gives \(x^2+x-6=40\), so \(x^2+x-46=0\). Do not forget to move \(-6\) to the other side.
Frequently asked questions
What is the correct answer to this question?
\(x^2+x-46=0\)
Why is this the correct answer?
For area, write \((x+3)(x-2)=40\). Expanding gives \(x^2+x-6=40\), so \(x^2+x-46=0\). Do not forget to move \(-6\) to the other side.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement